50m^2+40m-24=0

Solution for 50m^2+40m-24=0 equation:

50m^2+40m-24=0

a = 50; b = 40; c = -24;
Δ = b2-4ac
Δ = 402-4·50·(-24)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-80}{2*50}=\frac{-120}{100}
=-1+1/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+80}{2*50}=\frac{40}{100}
=2/5
$